首先看一下SoundPool的工具类方法

    //load 音频资源
    public static void loadAudioSources(Context context){
        soundMap.put(1, soundpool.load(context, R.raw.onenew, 1));
        soundMap.put(2, soundpool.load(context, R.raw.twonew, 1));
        soundMap.put(3, soundpool.load(context, R.raw.threenew, 1));
        soundMap.put(4, soundpool.load(context, R.raw.fournew, 1));
        soundMap.put(5, soundpool.load(context, R.raw.fivenew, 1));
        soundMap.put(6, soundpool.load(context, R.raw.sixnew, 1));
        soundMap.put(7, soundpool.load(context, R.raw.sevennew, 1));
        soundMap.put(8, soundpool.load(context, R.raw.eightnew, 1));
        soundMap.put(9, soundpool.load(context, R.raw.ninenew, 1));
        soundMap.put(10, soundpool.load(context, R.raw.zeronew, 1));
        soundMap.put(11, soundpool.load(context, R.raw.pleasenew, 1));
        soundMap.put(12, soundpool.load(context, R.raw.comenew, 1));
        soundMap.put(13, soundpool.load(context, R.raw.windownew, 1));
        soundMap.put(14, soundpool.load(context, R.raw.a, 1));
    }

    // play 音频资源
    public static void playAudio(int id){
        // rate：播放的速率，范围0.5-2.0(0.5为一半速率，1.0为正常速率，2.0为两倍速率)
        soundpool.play(soundMap.get(id), 1, 1, 0, 0, (float) 1.1);
    }

    /**
     * 获取语音播放的id
     * */
    public static int getSoundSpeaker(String str){
        switch (str){
            case "1":
                return 1;
            case "2":
                return 2;
            case "3":
                return 3;
            case "4":
                return 4;
            case "5":
                return 5;
            case "6":
                return 6;
            case "7":
                return 7;
            case "8":
                return 8;
            case "9":
                return 9;
            case "0":
                return 10;
            case "A":
                return 14;
            default:
                return 0;
        }
    }

当我们调用上述的playAudio方法时，就是播放对应的音频文件了。此时我们没有办法控制播放的过程，如果我们连续播放多个音频，就一定要注意播放时间的问题。只有播放完上一个音频，才能继续播放下一个音频，否则声音会重叠。如下代码，使用Thread.sleep等待语音播放。

    final Runnable mSpeakRunnableNew = new Runnable() {
        @Override
        public void run() {
            String WindowNum = "A4003";
            String NumDataNew = "01";
            int id = 0;
            try {
                // just for speaker
                Thread.sleep(200);
                SoundPoolUtil.playAudio(11);
                Thread.sleep(300);
                for (int i=0; i<WindowNum.length(); i++){
                    String str = String.valueOf(WindowNum.charAt(i));
                    Thread.sleep(260);
                    id = SoundPoolUtil.getSoundSpeaker(str);
                    if (id > 0) {
                        SoundPoolUtil.playAudio(id);
                    }
                }
                Thread.sleep(300);
                SoundPoolUtil.playAudio(12);
                Thread.sleep(200);
                for (int i=0; i<NumDataNew.length(); i++){
                    String str = String.valueOf(NumDataNew.charAt(i));
                    Thread.sleep(230);
                    id = SoundPoolUtil.getSoundSpeaker(str);
                    if (id > 0) {
                        SoundPoolUtil.playAudio(id);
                    }
                }
                Thread.sleep(300);
                SoundPoolUtil.playAudio(13);
            } catch (Exception e) {

            }
        }
    };

如果把所有需要播放的资源id放到一起，也可以使用以下方法

/**
 * 音频播放线程
 */
private class PlayThread extends Thread {
    @Override
    public void run() {
        Set<Integer> soundIdSet = soundIdMap.keySet();
        for (Integer soundId : soundIdSet) {
            soundPool.play(soundId, 1, 1, 0, 0, 1);
            try {
                //获取当前音频的时长
                Thread.sleep(soundIdMap.get(soundId));
            } catch (InterruptedException e) {
                e.printStackTrace();
            }
        }
    }
}